document.write( "Question 788969: Investor invested a total of $3400 in 2 mutual funds. One fund earned 4% profit and the other earned 2% profit. If the investor's total profit was $96 how much was invested in each mutual fund? \n" ); document.write( "
Algebra.Com's Answer #478695 by mananth(16946)\"\" \"About 
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Part I 4.00% per annum ------------- Amount invested =x
\n" ); document.write( "Part II 2.00% per annum ------------ Amount invested = y
\n" ); document.write( " 3400
\n" ); document.write( "Interest----- 96.00
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\n" ); document.write( "Part I 4.00% per annum ---x
\n" ); document.write( "Part II 2.00% per annum ---y
\n" ); document.write( "Total investment
\n" ); document.write( "x + 1 y= 3400 -------------1
\n" ); document.write( "Interest on both investments
\n" ); document.write( "4.00% x + 2.00% y= 96
\n" ); document.write( "Multiply by 100
\n" ); document.write( "4 x + 2 y= 9600.00 --------2
\n" ); document.write( "Multiply (1) by -4
\n" ); document.write( "we get
\n" ); document.write( "-4 x -4 y= -13600.00
\n" ); document.write( "Add this to (2)
\n" ); document.write( "0 x -2 y= -4000
\n" ); document.write( "divide by -2
\n" ); document.write( " y = 2000 - x)
\n" ); document.write( "Part I 4.00% $ 1400
\n" ); document.write( "Part II 2.00% $ 2000
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\n" ); document.write( "CHECK
\n" ); document.write( "1400 --------- 4.00% ------- 56.00
\n" ); document.write( "2000 ------------- 2.00% ------- 40.00
\n" ); document.write( "Total -------------------- 96.00
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\n" ); document.write( "m.ananth@hotmail.ca
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