document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=788943>Question 788943</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a motorist travels directly north for 40 km then turns to the west and goes 20km. how far is she from the starting point and in what direction? give the angle with respect to east. <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #478679 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=478679\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a motorist travels directly north for 40 km then turns to the west and goes 20km. how far is she from the starting point and in what direction? give the angle with respect to east. <BR>\n" );
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document.write( "She starts at (0,0)<BR>\n" );
document.write( "She ends up at (-20,40)<BR>\n" );
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document.write( "How far ?:: sqrt[20^2 +40^2] = sqrt[400+1600] = sqrt(2000) = 20sqrt(5) km<BR>\n" );
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document.write( "Angle ??:: tan^-1(40/-20) = tan^-1(-2) = 180-63.43 = 116.57 degrees<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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