document.write( "Question 788870: At constant temperature, the atmospheric pressure p (in Pa) at an altitude h (in m) is given by Ph = Poe^(-mgh/RT), where Po is the pressure where h = 0 (atmospheric pressure at sea level). Given that Po = 1013.25 hPa (atmospheric pressure at sea level) and Ph = 900 hPa, find the value of h.\r
\n" ); document.write( "\n" ); document.write( "Where P0 is the atmospheric pressure at some reference level
\n" ); document.write( "Ph is the atmospheric pressure at altitude h (m) above the reference level.
\n" ); document.write( "m is the molecular mass of air (0.0289644 kg/mol)
\n" ); document.write( "g is acceleration due to gravity (9.80665 ms-2)
\n" ); document.write( "R is the gas constant constant (8.314462 JK-1mol-1)
\n" ); document.write( "T is the temperature in Kelvin. In the lower altitudes temperature reduces with altitude at a rate of about 6.5 Kelvin per km of altitude.
\n" ); document.write( "

Algebra.Com's Answer #478670 by KMST(5328)\"\" \"About 
You can put this solution on YOUR website!
\"P%5Bh%5D+=+P%5B0%5D%2Ae%5E%22%28-mgh%2FRT%29%22\"
\n" ); document.write( "\"P%5Bh%5D%2FP%5B0%5D=e%5E%22%28-mgh%2FRT%29%22\" or \"P%5B0%5D%2FP%5Bh%5D=e%5E%22%28mgh%2FRT%29%22\"
\n" ); document.write( "\"ln%28P%5Bh%5D%2FP%5B0%5D%29=-mgh%2FRT\" or \"ln%28P%5B0%5D%2FP%5Bh%5D%29=mgh%2FRT\"
\n" ); document.write( "\"ln%281013.25%2F900%29=mgh%2FRT\" --> \"h=%28RT%2Fmg%29%2Aln%281013.25%2F900%29\"
\n" ); document.write( "Assuming that \"T\" is the temperature at sea level, or it does not change much from 0 to h meters above sea level,
\n" ); document.write( "\"h=%288.314462%2A6.5%2F%280.0289644%2A9.80665%29%29%2Aln%281013.25%2F900%29\" gives us the height in meters (because those would be the units of \"RT%2Fmg\"} with, R, T, m, and g in the units given).
\n" ); document.write( "I do not have a temperature, so I will assume \"20%5EoC\" (293 kelvins)
\n" ); document.write( "\"h=%288.314462%2A293%2F%280.0289644%2A9.80665%29%29%2Aln%281013.25%2F900%29=1017%29\"
\n" ); document.write( "So the height is about 1,000 meters.
\n" ); document.write( "
\n" );