document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=788756>Question 788756</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find three consecutive integers such that the sum of the first and the third increased by 8 is 40 more than the second. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #478611 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=478611\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let the integers be (n-1) , n, (n+1)\r<BR>\n" );
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document.write( "(n-1)+(n+1) +8 =n+40\r<BR>\n" );
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document.write( "2n+8=n+40\r<BR>\n" );
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document.write( "n=40-8<BR>\n" );
document.write( "n=32\r<BR>\n" );
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document.write( "The numbers are<BR>\n" );
document.write( "31 32 , 33\r<BR>\n" );
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