document.write( "Question 788754: On a drive from your home to town, you wish
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document.write( "to average 33.6 mph. The distance from your
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document.write( "home to town is 90 miles. However, at 45 miles
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document.write( "(half way), you find you have averaged only
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document.write( "25.2 mph.
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document.write( "What average speed must you maintain in
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document.write( "the remaining distance in order to have an
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document.write( "overall average speed of 33.6 mph?
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document.write( "Answer in units of mph \n" );
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Algebra.Com's Answer #478608 by mananth(16946)![]() ![]() You can put this solution on YOUR website! On a drive from your home to town, you wish \n" ); document.write( "to average 33.6 mph. The distance from your \n" ); document.write( "home to town is 90 miles. However, at 45 miles \n" ); document.write( "(half way), you find you have averaged only \n" ); document.write( "25.2 mph. \n" ); document.write( "What average speed must you maintain in \n" ); document.write( "the remaining distance in order to have an \n" ); document.write( "overall average speed of 33.6 mph? \n" ); document.write( "Answer in units of mph\r \n" ); document.write( "\n" ); document.write( "let the speed be x\r \n" ); document.write( "\n" ); document.write( "total average = 33.6 \n" ); document.write( "distance = 90\r \n" ); document.write( "\n" ); document.write( "time = 90/33.6\r \n" ); document.write( "\n" ); document.write( "Time first leg = 45/25.2\r \n" ); document.write( "\n" ); document.write( "Time second leg= 45/x\r \n" ); document.write( "\n" ); document.write( "45/25.2 + 45/x = 90/33.6\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " 45/x = 90/33.6 - 45/25.2 \r \n" ); document.write( "\n" ); document.write( "45/x = 0.893\r \n" ); document.write( "\n" ); document.write( "x= 45/0.893\r \n" ); document.write( "\n" ); document.write( "x=50.49 mph\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |