document.write( "Question 788781: A Travel Weekly International Air Transport Association survey asked business travelers about the
\n" ); document.write( "purpose for their most recent business trip. 19% responded that it was for an internal company visit.
\n" ); document.write( "Suppose 950 business travelers are randomly selected.
\n" ); document.write( "a. What is the probability that more than 25% of the business travelers say that the reason for their
\n" ); document.write( "most recent business trip was an internal company visit?
\n" ); document.write( "b. What is the probability that between 15% and 20% of the business travelers say that the reason for
\n" ); document.write( "their most recent business trip was an internal company visit?
\n" ); document.write( "c. What is the probability that between 133 and 171 of the business travelers say that the reason for
\n" ); document.write( "their most recent business trip was an internal company visit?
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Algebra.Com's Answer #478606 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
A Travel Weekly International Air Transport Association survey asked business travelers about the purpose for their most recent business trip. 19% responded that it was for an internal company visit.
\n" ); document.write( "p = 0.19
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\n" ); document.write( "Suppose 950 business travelers are randomly selected.
\n" ); document.write( "a. What is the probability that more than 25% of the business travelers say that the reason for their most recent business trip was an internal company visit?
\n" ); document.write( "z(0.25) = (0.25-0.19)/sqrt[0.19*0.81/950] = 1.4907
\n" ); document.write( "P(p > 0.25) = P(z > 1.4907) = 0.0680
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\n" ); document.write( "\n" ); document.write( "b. What is the probability that between 15% and 20% of the business travelers say that the reason for their most recent business trip was an internal company visit?
\n" ); document.write( "Find the z-values of 20% and 15%; then find the probability between them.
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\n" ); document.write( "c. What is the probability that between 133 and 171 of the business travelers say that the reason for their most recent business trip was an internal company visit?
\n" ); document.write( "Find 133/950 and 171/950
\n" ); document.write( "Find their z-values.
\n" ); document.write( "Find the probability between them.
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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