document.write( "Question 788633: A right triangle's height is 3 times the length of its base. If the area of the triangle is 54, what is the height?
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Algebra.Com's Answer #478573 by waynest(281) ![]() You can put this solution on YOUR website! height = 3x \n" ); document.write( "base = x \n" ); document.write( "Area = 54\r \n" ); document.write( "\n" ); document.write( "1/2bh \n" ); document.write( "1/2(3x)x = 54 \n" ); document.write( "1/2(3x^2) = 54 \n" ); document.write( "2(1/2)3x^2 = 2(54) \n" ); document.write( "3x^2 = 108 \n" ); document.write( "3x^2/3 = 108/3 \n" ); document.write( "x^2 = 36 \n" ); document.write( "sqrtX^2 = sqrt36 \n" ); document.write( "x = 6\r \n" ); document.write( "\n" ); document.write( "check: \n" ); document.write( "1/2(3(6))6 \n" ); document.write( "1/2(108 = 54 \n" ); document.write( "54 = 54 \n" ); document.write( " |