document.write( "Question 788633: A right triangle's height is 3 times the length of its base. If the area of the triangle is 54, what is the height?
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Algebra.Com's Answer #478573 by waynest(281)\"\" \"About 
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height = 3x
\n" ); document.write( "base = x
\n" ); document.write( "Area = 54\r
\n" ); document.write( "\n" ); document.write( "1/2bh
\n" ); document.write( "1/2(3x)x = 54
\n" ); document.write( "1/2(3x^2) = 54
\n" ); document.write( "2(1/2)3x^2 = 2(54)
\n" ); document.write( "3x^2 = 108
\n" ); document.write( "3x^2/3 = 108/3
\n" ); document.write( "x^2 = 36
\n" ); document.write( "sqrtX^2 = sqrt36
\n" ); document.write( "x = 6\r
\n" ); document.write( "\n" ); document.write( "check:
\n" ); document.write( "1/2(3(6))6
\n" ); document.write( "1/2(108 = 54
\n" ); document.write( "54 = 54
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