document.write( "Question 788648: gummy bears sell for $3.50 per pound is to be mixed with jelly beans which sell for $5.50 per pound to obtain 6o pounds to sell at $4.00 per pound How many pounds of Jelly beans do you need? thank you! \n" ); document.write( "
Algebra.Com's Answer #478569 by josgarithmetic(39620)\"\" \"About 
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g for Gummy bears, j for Jelly beans, their counts in pounds.\r
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\n" ); document.write( "\n" ); document.write( "Accounting for cost, \"3.5g%2B5.5j=4.00%2860%29\"\r
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\n" ); document.write( "\n" ); document.write( "Accounting for pounds of the mixture, \"g%2Bj=60\"\r
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\n" ); document.write( "\n" ); document.write( "Simplify the cost equation before handling the system.
\n" ); document.write( "\"35g%2B55j=10%2A240\"
\n" ); document.write( "\"7g%2B11j=2%2A240\"
\n" ); document.write( "\"7g%2B11j=480\"\r
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\n" ); document.write( "\n" ); document.write( "The system to use may best begin in these two equations:
\n" ); document.write( "\"highlight%287g%2B11j=480%29\"
\n" ); document.write( "\"highlight%28g%2Bj=60%29\"\r
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\n" ); document.write( "\n" ); document.write( "Solving the system: multiply 7*R2 and subtract from R1. Find value of j; from this find value for g.\r
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\n" ); document.write( "Here is that described solving process carried to completion.
\n" ); document.write( "\"g%2Bj=60\", same as \"7g%2B7j=420\".
\n" ); document.write( "\"%287g%2B11j%29-%287g%2B7j%29=480-420\"
\n" ); document.write( "\"7g%2B11j-7g-7j=60\"
\n" ); document.write( "\"11j-7j=60\"
\n" ); document.write( "\"4j=60\"
\n" ); document.write( "\"j=15\"
\n" ); document.write( "Using that back in the R2 equation or the pound-sum equation, you find \"g=45\".
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