document.write( "Question 788639: Find the x intercept of these parabola by completing the square
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document.write( "a)y=x^2-4x+1
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document.write( "b)y=2x^2-12x-7\r
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document.write( "Can you please help me out? Thanks so much in advance:)
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document.write( "Can you please show all the steps it would really help me understand better thank you:) \n" );
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Algebra.Com's Answer #478566 by waynest(281)![]() ![]() ![]() You can put this solution on YOUR website! x^2 -4x + 1 \n" ); document.write( " x^2 -4x + (-4/2)^2 - (-4/2)^2 + 1 \n" ); document.write( " x^2 -4x + 4 - 4 + 1 \n" ); document.write( "(x - 2)^2 - 3 \n" ); document.write( "(x - 2)^2 = 3 \n" ); document.write( "sqrt(x - 2)^2 = +-sqrt3 \n" ); document.write( "x - 2 = +- sqrt3 \n" ); document.write( "x = 2+- sqrt3\r \n" ); document.write( "\n" ); document.write( "x = 2+ sqrt 3 \n" ); document.write( "x = 3.73\r \n" ); document.write( "\n" ); document.write( "x = 2 - sqrt3 \n" ); document.write( "x = 0.27\r \n" ); document.write( "\n" ); document.write( "2x^2 -12x -7 \n" ); document.write( "divide by 2 \n" ); document.write( "x^2 - 6x -3.5 \n" ); document.write( "x^2 - 6x + (-6/2)^2 - (-6/2)^2 - 3.5 \n" ); document.write( "x^2 - 6x + 9 -9 -3.5 \n" ); document.write( "(x - 3)^2 -12.5 = 0 \n" ); document.write( "(x - 3)^2 = 12.5 \n" ); document.write( "sqrt(x - 3)^2 = +-sqrt12.5 \n" ); document.write( "x - 3 = +- sqrt12.5 \n" ); document.write( "x = 3 +- sqrt12.5\r \n" ); document.write( "\n" ); document.write( "x = 3 + sqrt12.5 \n" ); document.write( "x = 6.54\r \n" ); document.write( "\n" ); document.write( "x = 3 - sqrt12.5 \n" ); document.write( "x = -0.54 \n" ); document.write( " \n" ); document.write( " |