document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=67267>Question 67267</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 3(3x-2)  = 5 -   2(2x-3)<BR>\n" );
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document.write( "10                  5   <BR>\n" );
document.write( " <BR>\n" );
document.write( "This should read   3(3x-2) over 10 is equal to 5 minus 2(2x-3) over 5.  I would appreciate the view of the workings as I need to see where I am going wrong. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #47854 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=47854\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3(3x-2)  = 5 -   2(2x-3)<BR>\n" );
document.write( "-------          -------<BR>\n" );
document.write( "10                  5   <BR>\n" );
document.write( "-----------------------<BR>\n" );
document.write( "Multiply thru by 10 to get rid of the denominators:<BR>\n" );
document.write( "3(3x-2) = 50 - 4(2x-3)<BR>\n" );
document.write( "Use the distributive law to get:\r<BR>\n" );
document.write( "\n" );
document.write( "9x-6 = 50 -8x+12<BR>\n" );
document.write( "Combine the x-terms on one side and the numbers on the other:<BR>\n" );
document.write( "17x = 78<BR>\n" );
document.write( "Divide both sides by 17 to get:<BR>\n" );
document.write( "x=4.588...<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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