document.write( "Question 788515: Find, to the nearest tenth of a degree, all positive angles less than 360° where cos  = -0.5982.
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Algebra.Com's Answer #478530 by stanbon(75887)\"\" \"About 
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Find, to the nearest tenth of a degree, all positive angles less than 360° where cos(x) = -0.5982
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\n" ); document.write( "x = cos^-1(-0.5982) = 107.35 degrees or 360-107.35 = 252.65 degrees
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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