document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=788371>Question 788371</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A 6.0% solution and a 13.0% solution of a drug are added to 200 mL  of a 24.0% solution to make 1500 mL of a 12.0% solution. The following equations relate to the milliliters of the added solutions. The number of milliliters of the added solution are represented by x and y, respectively. Find x and y (to three significant digits)                 x+y+200= 1500                .06x+.12y+.24(200)=.12(1500)\r<BR>\n" );
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document.write( "can someone show me how to do this with steps\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #478491 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=478491\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> we are given two equations in two unknowns<BR>\n" );
document.write( "x+y+200= 1500<BR>\n" );
document.write( ".06x+.12y+.24(200)=.12(1500)<BR>\n" );
document.write( "subtract 200 from both sides of the = in the first equation<BR>\n" );
document.write( "x+y = 1300 and<BR>\n" );
document.write( "y = 1300 - x<BR>\n" );
document.write( "now multiply percentages in second equation<BR>\n" );
document.write( ".06x +.12y +48 = 180<BR>\n" );
document.write( "subtract 48 from both sides of =<BR>\n" );
document.write( ".06x +.12y = 132<BR>\n" );
document.write( "now substitute 1300-x for y<BR>\n" );
document.write( ".06x +.12*(1300-x) = 132<BR>\n" );
document.write( ".06x +156 -.12x = 132<BR>\n" );
document.write( "subtract 132 from both sides of =<BR>\n" );
document.write( ".06x +24 -.12x =0<BR>\n" );
document.write( ".06x = 24<BR>\n" );
document.write( "x = 400 mL<BR>\n" );
document.write( "400 +y = 1300<BR>\n" );
document.write( "y = 900 mL<BR>\n" );
document.write( "now<BR>\n" );
document.write( ".06 * 400 = 24 mL of 6% solution<BR>\n" );
document.write( ".12 * 900 = 108 mL of 12% solution, checking<BR>\n" );
document.write( "24 +108 +48 = 180<BR>\n" );
document.write( "180 = 180\r<BR>\n" );
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