document.write( "Question 788340: If tan x = 2.4, what is cos x \n" ); document.write( "
Algebra.Com's Answer #478481 by Alan3354(69443)\"\" \"About 
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If tan x = 2.4, what is cos x
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\n" ); document.write( "sec^2 = tan^2 + 1 = 6.76
\n" ); document.write( "sec = 2.6
\n" ); document.write( "cos = 1/(2.6)
\n" ); document.write( "or -1/(2.6), the quadrant wasn't given.
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