document.write( "Question 788163: what weight of am alloy containing 10% silver must be melted with an alloy containing60% silver to obtain 10lbs of an alloy contain 40% silver \n" ); document.write( "
Algebra.Com's Answer #478426 by mananth(16946)\"\" \"About 
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percent ---------------- quantity
\n" ); document.write( "Silver Alloy I 10.00% ---------------- x pounds
\n" ); document.write( "Silver Alloy II 60.00% ------ 10 - x pounds
\n" ); document.write( "Mixture 40.00% ---------------- 10
\n" ); document.write( "Total 10 pounds
\n" ); document.write( "10.00% x + 60.00% ( 10 - x ) = 40.00% * 10
\n" ); document.write( "10 x + 60 ( 10 - x ) = 400
\n" ); document.write( "10 x + 600 - 60 x = 400
\n" ); document.write( "10 x - 60 x = 400 - -600
\n" ); document.write( "-50 x = -200
\n" ); document.write( "/ -50
\n" ); document.write( " x = 4 pounds 10.00% Silver Alloy I
\n" ); document.write( " 6 pounds 60.00% Silver Alloy II
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\n" ); document.write( "m.ananth@hotmail.ca
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