document.write( "Question 788121: how do i figure the answer of \"r\"\r
\n" ); document.write( "\n" ); document.write( "1 R R
\n" ); document.write( "- R - - = -
\n" ); document.write( "2 3 12\r
\n" ); document.write( "\n" ); document.write( "1 over 2 r minus r over 3 equals r over 12 \n" ); document.write( "
Algebra.Com's Answer #478411 by xinxin(76)\"\" \"About 
You can put this solution on YOUR website!
R* (1/2 - 1/3) = R * 1/12
\n" ); document.write( "R will be reduced so you cannot calculate its value. In other words, R can have any value.
\n" ); document.write( "The funny thing is that the equation is not even equal...1/2 - 1/3 = 1/6, 1/6 is not equal to 1/12.\r
\n" ); document.write( "\n" ); document.write( "If the first R was in denominator, it would have a value:
\n" ); document.write( "1/2R - R/3 =R/12
\n" ); document.write( "1/2R - R/3 + R/3 = R/12 + R/3
\n" ); document.write( "1/2R = R/12 + R/3
\n" ); document.write( "1/2R = R/12 + 4R/12
\n" ); document.write( "1/2R = 5R/12
\n" ); document.write( "1/2R * 2R = 5R/12 * 2R
\n" ); document.write( "1 = 10R^2/12
\n" ); document.write( "1 * 12 = 10R^2/12 *12
\n" ); document.write( "12 = 10R^2
\n" ); document.write( "12/10 = 10R^2/10
\n" ); document.write( "R^2 = 12/10 = 6/5
\n" ); document.write( "R = + √6/5, or R = -√6/5
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