document.write( "Question 788059: A truck passes a highway patrol station going 70 km/hr. When the truck is 10 kilometers past the station, a patrol car starts after it going 100 km/hr. Let t be the number of hours the patrol car has been going.
\n" ); document.write( "a) What expression represents the patrol car's distance from the station? What expression represents the trucks distanxe from the station after t hours?
\n" ); document.write( "b) When does the patrol car catch the truck?
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Algebra.Com's Answer #478398 by KMST(5328)\"\" \"About 
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\"t\"= number of hours the patrol car has been going.
\n" ); document.write( "a) What expression represents the patrol car's distance from the station?
\n" ); document.write( "\"100%2At=100t\"= patrol car's distance from the station, in km.
\n" ); document.write( "What expression represents the truck's distance from the station after t hours?
\n" ); document.write( "The truck was 10 km past the station at \"t=0\" (when the patrol car started the chase), so
\n" ); document.write( "\"10%2B70%2At=70t%2B10\"= truck's distance from the station t hours after the patrol car starts chasing it.
\n" ); document.write( "b) When does the patrol car catch the truck?
\n" ); document.write( "When they at at the same distance from the station, the solution to the equation
\n" ); document.write( "\"100t=70t%2B10\"
\n" ); document.write( "Solving:
\n" ); document.write( "\"100t=70t%2B10\"-->\"100t-70t=70t%2B10-70t\"-->\"%28100-70%29t=10\"-->\"30t=10\"-->\"t=10%2F30\"-->\"t=1%2F3\"
\n" ); document.write( "The patrol car catches the truck after \"1%2F3\" of an hour, which is
\n" ); document.write( "\"%281%2F3%29%2A%2860minutes%29=20minutes\"
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\n" ); document.write( "PS_ What I do not understand is why the patrol car was chasing the truck. 70 km/h is only about 45 miles per hour, and that is not too fast for a highway.
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