document.write( "Question 787931:  Fred can ride a scooter at 15mph. Tom can pedal a bike at 9mph. They started at the same time travelling the same distance. Fred arrives at the destination 20 minutes ahead of Tom.\r
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document.write( "a)How long does it take Tom to arrive at the destination?
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document.write( "b)How far is the trip from starting point to destination?\r
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document.write( "PLEASE HELP!!! \n" );
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| Algebra.Com's Answer #478370 by solver91311(24713)     You can put this solution on YOUR website! \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Distance equals rate times time.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Note that 20 minutes is \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Let \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "From the above information we can say:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "or\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Since \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Solve for \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Then multiply 15 times t to get the distance. Multiply 9 times \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "John \n" ); document.write( " \n" ); document.write( "Egw to Beta kai to Sigma \n" ); document.write( "My calculator said it, I believe it, that settles it \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |