document.write( "Question 67227This question is from textbook Advanced mathematics
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document.write( ": How many three-digit counting numbers that are less than 300 are there such that all the digits are odd? \n" );
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Algebra.Com's Answer #47832 by 303795(602)![]() ![]() ![]() You can put this solution on YOUR website! The only numbers below 300 must be in the one hundreds so the first digit must be 1. \n" ); document.write( "The second digit can be 1, 3, 5, 7 or 9. \n" ); document.write( "Five numbers with a second digit of 1 have an odd third digit. \n" ); document.write( "Five numbers with a second digit of 3 have an odd third digit. \n" ); document.write( "Five numbers with a second digit of 5 have an odd third digit. \n" ); document.write( "Five numbers with a second digit of 7 have an odd third digit. \n" ); document.write( "Five numbers with a second digit of 9 have an odd third digit.\r \n" ); document.write( "\n" ); document.write( "So the total is 25 numbers. \n" ); document.write( "111, 113, 115, 117, 119, 131, 133, 135, 137, 139, 151, 153, 155, 157, 159, 171, 173, 175, 177, 179, 191, 193, 195, 197, 199 \n" ); document.write( " \n" ); document.write( " |