document.write( "Question 787709: A mother is presently four times as old as her daughter.If the sum of their ages 6 years ago was 48, find their present ages \n" ); document.write( "
Algebra.Com's Answer #478281 by stanbon(75887)\"\" \"About 
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A mother is presently four times as old as her daughter.If the sum of their ages 6 years ago was 48, find their present ages
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\n" ); document.write( "Equations:
\n" ); document.write( "m = 4d
\n" ); document.write( "m-6 + d-6 = 48
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\n" ); document.write( "Substitute for \"m\" and solve for \"d\":
\n" ); document.write( "4d-6 + d-6 = 48
\n" ); document.write( "5d - 12 = 48
\n" ); document.write( "5d = 60
\n" ); document.write( "d = 12 years (daughter's age now)
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\n" ); document.write( "Solve for \"m\":
\n" ); document.write( "m = 4d
\n" ); document.write( "m = 4*12 = 48 (mom's age now)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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