document.write( "Question 787709: A mother is presently four times as old as her daughter.If the sum of their ages 6 years ago was 48, find their present ages \n" ); document.write( "
Algebra.Com's Answer #478281 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! A mother is presently four times as old as her daughter.If the sum of their ages 6 years ago was 48, find their present ages \n" ); document.write( "------- \n" ); document.write( "Equations: \n" ); document.write( "m = 4d \n" ); document.write( "m-6 + d-6 = 48 \n" ); document.write( "-------------------- \n" ); document.write( "Substitute for \"m\" and solve for \"d\": \n" ); document.write( "4d-6 + d-6 = 48 \n" ); document.write( "5d - 12 = 48 \n" ); document.write( "5d = 60 \n" ); document.write( "d = 12 years (daughter's age now) \n" ); document.write( "------ \n" ); document.write( "Solve for \"m\": \n" ); document.write( "m = 4d \n" ); document.write( "m = 4*12 = 48 (mom's age now) \n" ); document.write( "=========== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "============= \n" ); document.write( " |