document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=787678>Question 787678</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of two numbers is 140. One number is five less than four times the other. Find the numbers. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #478264 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=478264\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let the numbers be x & y \r<BR>\n" );
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document.write( "x+y=140.................(1)\r<BR>\n" );
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document.write( "x= 4y-5\r<BR>\n" );
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document.write( "substitute  x in (1)\r<BR>\n" );
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document.write( "4y-5+y=140\r<BR>\n" );
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document.write( "5y-5=140<BR>\n" );
document.write( "5y=140+5<BR>\n" );
document.write( "5y=145<BR>\n" );
document.write( "/5<BR>\n" );
document.write( "y=29\r<BR>\n" );
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document.write( "you can find x </SPAN>\n" );
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