document.write( "Question 787646: How many liters of water must be mixed with 20 liters of a 90% alcohol mixture so that the alcohol content of the mixture is reduced to 50%\r
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document.write( "Is my equation correct?
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document.write( "20(0.90) - x (0.50) = x\r
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document.write( "thank you for helping me \n" );
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Algebra.Com's Answer #478258 by mananth(16949) You can put this solution on YOUR website! --- percent ---------------- Amount \n" ); document.write( "Alcohhol 90 ---------------- 20 liters \n" ); document.write( "Water 0 ---------------- x liters \n" ); document.write( "Mixture 50 ---------------- 20 + x liters \n" ); document.write( " \n" ); document.write( "90 * 20 + 0 x = 50 ( 20 + x ) \n" ); document.write( "1800 + 0 x = 1000 + 50 x \n" ); document.write( "0 x -50 x = -1800 + 1000 \n" ); document.write( "-50 x = -800 \n" ); document.write( "/ -50 \n" ); document.write( "x = 16 liters Water \n" ); document.write( " \n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " \n" ); document.write( " |