document.write( "Question 787624: I nee help with 2 questions. \r
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document.write( "cot (cos^-1(-5/13))\r
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document.write( "sec (sin^-1 (x)) \n" );
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Algebra.Com's Answer #478244 by lwsshak3(11628) ![]() You can put this solution on YOUR website! cot (cos^-1(-5/13)) \n" ); document.write( "& \n" ); document.write( "sec (sin^-1 (x)) \n" ); document.write( "*** \n" ); document.write( "let u=angle whose cos=(-5/13) \n" ); document.write( "or cos(u)=(-5/13) \n" ); document.write( "sin(u)=√(1-cos^2(x))=√(1-25/169)=√(144/169)=12/13 \n" ); document.write( "cot(u)=cos(u)/sin(u)=-5/12 \n" ); document.write( ".. \n" ); document.write( "let v=angle whose sin=x \n" ); document.write( "or sin(v)=x \n" ); document.write( "cos(v)=√(1-sin^2(v))=√(1-x^2) \n" ); document.write( "sec(v)=1/cos(v)=1/√(1-x^2) \n" ); document.write( ".. \n" ); document.write( "cot (cos^-1(-5/13))=-5/12 \n" ); document.write( "sec (sin^-1 (x))=1/√(1-x^2) \n" ); document.write( ".. \n" ); document.write( "Note: the inverse of a trig function is always an angle \n" ); document.write( " |