document.write( "Question 787558: Give a general solution in radians using the unit circle
\n" ); document.write( "3 tan of x minus the square root of three equals zero
\n" ); document.write( "3 tan of x equals the square root of three
\n" ); document.write( "tan of x equals square root of 3 over 3
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Algebra.Com's Answer #478243 by KMST(5328)\"\" \"About 
You can put this solution on YOUR website!
\"3tan%28x%29-sqrt%283%29=0\"
\n" ); document.write( "\"3tan%28x%29=sqrt%283%29\"
\n" ); document.write( "\"tan%28x%29=sqrt%283%29%2F3\"
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\n" ); document.write( "We know that \"tan%28pi%2F6%29=sqrt%283%29%2F3\" (or \"tan%2830%5Eo%29=sqrt%283%29%2F3\" if using degrees). For that angle \"sin%28pi%2F6%29=1%2F2\" and \"cos%28pi%2F6%29=sqrt%283%29%2F2\"
\n" ); document.write( "That is the only solution for \"-pi%2F2%3Cx%3Cpi%2F2\" (or \"-90%5Eo%3Cx%3C90%5Eo\" if using degrees).
\n" ); document.write( "The function does not exist for \"x=-pi%2F2\" or \"x=pi%2F2\", where \"cos%28x%29=0\".
\n" ); document.write( "In between those values \"tan%28x%29\" increases continuously.
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\n" ); document.write( "We also know that if \"tan%28x%29\" exists, \"tan%28x%2Bpi%29=tan%28x%29\", so the funcion's values repeat at \"pi\" intervals, and we say that the function has period \"pi\".
\n" ); document.write( "So there are infinite solutions that can be all expressed as
\n" ); document.write( "\"highlight%28x=pi%2F6%2Bk%2Api%29\" for all \"k\" integers (or \"highlight%28x=30%5Eo%2Bk%2A180%5Eo%29\" for all \"k\" integers if you measure angles in degrees).
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