document.write( "Question 787574: A car and a motorcycle both leave from the same point and travel in the same direction. (See the illustration.) The car travels at an average rate of 55 mph and the motorcycle at an average rate of 40 mph. How long will it take before the vehicles are 5 miles apart?
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Algebra.Com's Answer #478233 by josmiceli(19441) $\"\"$ $\"About$

You can put this solution on YOUR website!
Let $\"+t+\"$ = time in hours when the vehicles are
\n" ); document.write( " $\"+5+\"$ mi apart
\n" ); document.write( "Let $\"+d+\"$ = distance the car travels in $\"+t+\"$ hrs
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\n" ); document.write( "Equation for car:
\n" ); document.write( "(1) $\"+d+=+55t+\"$
\n" ); document.write( "Equation for motorcycle:
\n" ); document.write( "(2) $\"+d+-+5+=+40t+\"$
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\n" ); document.write( "Substitute (1) into (2)
\n" ); document.write( "(2) $\"+55t+-+5+=+40t+\"$
\n" ); document.write( "(2) $\"+15t+=+5+\"$
\n" ); document.write( "(2) $\"+t+=+1%2F3+\"$
\n" ); document.write( " $\"+%281%2F3%29%2A60+=+20+\"$
\n" ); document.write( "They will be 5 mi apart in 20 minutes
\n" ); document.write( "check:
\n" ); document.write( "(1) $\"+d+=+55%2A%281%2F3%29+\"$
\n" ); document.write( "(1) $\"+d+=+55%2F3+\"$
\n" ); document.write( "and
\n" ); document.write( "(2) $\"+d+-+5+=+40%2A%281%2F3%29+\"$
\n" ); document.write( "(2) $\"+d+=+15%2F3+%2B+40%2F3+\"$
\n" ); document.write( "(2) $\"+d+=+55%2F3+\"$
\n" ); document.write( "OK
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