document.write( "Question 787559: How do I solve this simultaneous logarithm.
\n" ); document.write( "log (x-4)+ 2 log y = log 16
\n" ); document.write( "log x + log y = 16
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Algebra.Com's Answer #478225 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
log (x-4)+ 2 log y = log 16
\n" ); document.write( "log x + log y = 16
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\n" ); document.write( "Modify for elimination:
\n" ); document.write( "log(x-4) + 2log(y) = log(16)
\n" ); document.write( "2log(x) + 2log(y) = 32
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\n" ); document.write( "Subtract and solve for \"x\":
\n" ); document.write( "2log(x) - log(x-4) = 32-log(16)
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\n" ); document.write( "log(x^2) - log(x-4) + log(16) = 32
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\n" ); document.write( "log[16x^2/(x-4)] = 32
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\n" ); document.write( "16x^2/(x-4) = 10^32
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\n" ); document.write( "16x^2 -10^32x -4*10^32 = 0
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\n" ); document.write( "Solve for \"x\"; then solve for \"y\".
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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