document.write( "Question 787559: How do I solve this simultaneous logarithm.
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document.write( "log (x-4)+ 2 log y = log 16
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document.write( "log x + log y = 16 \n" );
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Algebra.Com's Answer #478225 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! log (x-4)+ 2 log y = log 16 \n" ); document.write( "log x + log y = 16 \n" ); document.write( "--------- \n" ); document.write( "Modify for elimination: \n" ); document.write( "log(x-4) + 2log(y) = log(16) \n" ); document.write( "2log(x) + 2log(y) = 32 \n" ); document.write( "------ \n" ); document.write( "Subtract and solve for \"x\": \n" ); document.write( "2log(x) - log(x-4) = 32-log(16) \n" ); document.write( "-------- \n" ); document.write( "log(x^2) - log(x-4) + log(16) = 32 \n" ); document.write( "---------------- \n" ); document.write( "log[16x^2/(x-4)] = 32 \n" ); document.write( "----------------- \n" ); document.write( "16x^2/(x-4) = 10^32 \n" ); document.write( "---- \n" ); document.write( "16x^2 -10^32x -4*10^32 = 0 \n" ); document.write( "---- \n" ); document.write( "Solve for \"x\"; then solve for \"y\". \n" ); document.write( "============================= \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "=============== \n" ); document.write( " |