document.write( "Question 787328: Can someone show me how to write the formula for this in math terms and solve it? I tried several ways but could not write the formula or solve it correctly. Thanks in advance for your time and efforts.
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document.write( " Pat is 3 times as old as she was 14 years ago. In 7 years, she will be 4 times as old as she was 14 years ago. How old is she now? \n" );
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Algebra.Com's Answer #478196 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Pat is 3 times as old as she was 14 years ago. In 7 years, she will be 4 times as old as she was 14 years ago. \n" ); document.write( " How old is she now? \n" ); document.write( ": \n" ); document.write( "Let a = Pat's age now \n" ); document.write( ": \n" ); document.write( "Write an equation for each statement, simplify: \n" ); document.write( ": \n" ); document.write( "\"Pat is 3 times as old as she was 14 years ago.\" \n" ); document.write( "a = 3(a-14) \n" ); document.write( "a = 3a - 42 \n" ); document.write( "42 = 3a - a \n" ); document.write( "42 = 2a \n" ); document.write( "a = 42/2 \n" ); document.write( "a = 21 yrs now \n" ); document.write( ": \n" ); document.write( "\" In 7 years, she will be 4 times as old as she was 14 years ago.' \n" ); document.write( "a + 7 = 4(a-14) \n" ); document.write( "a + 7 = 4a - 56 \n" ); document.write( "a = 4a - 56 - 7 \n" ); document.write( "a = 4a - 63 \n" ); document.write( "63 = 4a - a \n" ); document.write( "63 = 3a \n" ); document.write( "a = 63/3 \n" ); document.write( "a = 21 yrs now, which we already knew.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |