document.write( "Question 787184: The perimeter of a rectangle is 41 in and its area is 91 sq inches. find th elength of its shortest side. \n" ); document.write( "

Algebra.Com's Answer #478133 by Cromlix(4381) $\"\"$ $\"About$

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Area = length*breadth
\n" ); document.write( "91 = l * b
\n" ); document.write( "Length = 91/b
\n" ); document.write( "Perimeter = 2*length + 2*breadth
\n" ); document.write( "41 = 2(91/b) + 2b
\n" ); document.write( "41 = 182/b + 2b
\n" ); document.write( "Common denominator = b
\n" ); document.write( "41b = 182 + 2b^2
\n" ); document.write( "2b^2 - 41b + 182 = 0
\n" ); document.write( "(2b - 13)(b - 14) = 0
\n" ); document.write( "2b - 13 = 0
\n" ); document.write( " b = 13/2
\n" ); document.write( "b = 6.5 inches
\n" ); document.write( "b - 14 = 0
\n" ); document.write( "b = 14 inches
\n" ); document.write( "Shortest side = 6.5 inches.
\n" ); document.write( "Hope this helps.
\n" ); document.write( ":-) \n" ); document.write( "

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