document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=787187>Question 787187</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A right triangle has an area of 48cm^2 with one side that is twice as long as the other side.  What is the hypotenuse of this triangle?  The answer is 4 square foots 15.  \r<BR>\n" );
document.write( "\n" );
document.write( "I know these formulas: A=1/2 the base*height and the pythagoream therom <BR>\n" );
document.write( "a^2 + b^2 = c^2.\r<BR>\n" );
document.write( "\n" );
document.write( "I was trying to solve by doing the following: 48= 1/2b * 2b; the \"2's\" cancel.<BR>\n" );
document.write( "48=b*b -----> 48=b^2.  I can place the 48 into the pythagoream therom; however, I still have 2 variables and I do not know how to solve. a^2 + 48 = c^2.  <BR>\n" );
document.write( "Thank you for your help.<BR>\n" );
document.write( "Shanell </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #478126 by </B><A HREF=/tutors/aboutme.mpl?userid=Cromlix><B>Cromlix(4381)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Cromlix><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Cromlix><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=478126\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Hi Shanell,<BR>\n" );
document.write( "If you make one of the sides of your<BR>\n" );
document.write( "triangle = x. <BR>\n" );
document.write( "And the other 2x (Twice the length)<BR>\n" );
document.write( "Area of a triangle = 1/2(base * height)<BR>\n" );
document.write( "48 = 1/2 (x * 2x)<BR>\n" );
document.write( "48 = x^2<BR>\n" );
document.write( "x = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%2848%29 ALIGN=MIDDLE  ALT=\"sqrt%2848%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "So, one side of your triangle<BR>\n" );
document.write( "would equal = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%2848%29 ALIGN=MIDDLE  ALT=\"sqrt%2848%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "And the other side = 2 * <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%2848%29 ALIGN=MIDDLE  ALT=\"sqrt%2848%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "= <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%28192%29 ALIGN=MIDDLE  ALT=\"sqrt%28192%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "As you said Pythagoras =<BR>\n" );
document.write( "a^2 + b^2 = c^2<BR>\n" );
document.write( "Squaring a square root leaves the number<BR>\n" );
document.write( "So, 48 + 192 = c^2<BR>\n" );
document.write( "c^2 = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%28240%29 ALIGN=MIDDLE  ALT=\"sqrt%28240%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "c = 4 square root 15.<BR>\n" );
document.write( "Hope this helps.<BR>\n" );
document.write( ":-) </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );