document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=787123>Question 787123</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A rectangle is 7 meters longer than it is wide. If the perimeter of the rectangle is 50 meters, find its area.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #478124 by </B><A HREF=/tutors/aboutme.mpl?userid=Cromlix><B>Cromlix(4381)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Cromlix><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Cromlix><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=478124\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Width = x<BR>\n" );
document.write( "Length = x + 7<BR>\n" );
document.write( "Perimeter = 2*width + 2*length<BR>\n" );
document.write( "50 = 2(x) + 2(x + 7)<BR>\n" );
document.write( "50 = 2x + 2x + 14<BR>\n" );
document.write( "Collect like terms<BR>\n" );
document.write( "4x = 50 - 14<BR>\n" );
document.write( "4x = 36<BR>\n" );
document.write( "x = 9<BR>\n" );
document.write( "Width = 9 metres<BR>\n" );
document.write( "Length = 16 metres.<BR>\n" );
document.write( "Hope this helps.<BR>\n" );
document.write( ":-) </SPAN>\n" );
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