document.write( "Question 787093: the perimeter of a playing field is 488 the legnth of the field is 6 yards less than quadruple the width. what are the dimensions of the field \n" ); document.write( "
Algebra.Com's Answer #478119 by Cromlix(4381)\"\" \"About 
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Width = x
\n" ); document.write( "Length = 4x - 6
\n" ); document.write( "Perimeter = 2*width + 2*length
\n" ); document.write( "488 = 2(x) + 2(4x - 6)
\n" ); document.write( "488 = 2x + 8x - 12
\n" ); document.write( "Collect like terms
\n" ); document.write( "10x = 488 + 12
\n" ); document.write( "10x = 500
\n" ); document.write( "x = 50
\n" ); document.write( "Width = 50 yards
\n" ); document.write( "Length = 194 yards.
\n" ); document.write( "Hope this helps.
\n" ); document.write( ":-) \n" ); document.write( "
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