document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=787159>Question 787159</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If the perimeter of a tennis court is 228 feet and the width is three less than half the length, what are the dimensions of the tennis court? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #478114 by </B><A HREF=/tutors/aboutme.mpl?userid=Cromlix><B>Cromlix(4381)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Cromlix><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Cromlix><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=478114\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Length = x<BR>\n" );
document.write( "Width = x/2 - 3<BR>\n" );
document.write( "Perimeter = 2*length + 2*width<BR>\n" );
document.write( "228 = 2(x) + 2(x/2 -3)<BR>\n" );
document.write( "228 = 2x + 2([x - 6]/2) In bracket  common denominator = 2)<BR>\n" );
document.write( "228 = 2x + x - 6<BR>\n" );
document.write( "3x = 228 + 6<BR>\n" );
document.write( "3x = 234<BR>\n" );
document.write( "x = 78<BR>\n" );
document.write( "Length = 78 feet<BR>\n" );
document.write( "Width = 36 feet<BR>\n" );
document.write( "Hope this helps.<BR>\n" );
document.write( ":-) </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );