document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=787072>Question 787072</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a rectangle has a perimeter of 68 feet. its length is 5 less than twice its width. find the area of the rectangle? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #478081 by </B><A HREF=/tutors/aboutme.mpl?userid=Cromlix><B>Cromlix(4381)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Cromlix><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Cromlix><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=478081\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Width = x<BR>\n" );
document.write( "Length = 2x - 5<BR>\n" );
document.write( "Perimeter = 2*width + 2*length<BR>\n" );
document.write( "68 = 2(x) + 2(2x - 5)<BR>\n" );
document.write( "68 = 2x + 4x - 10<BR>\n" );
document.write( "68 + 10 = 6x<BR>\n" );
document.write( "78 = 6x<BR>\n" );
document.write( "x = 13 feet<BR>\n" );
document.write( "Width = 13 feet<BR>\n" );
document.write( "Length = 21 feet<BR>\n" );
document.write( "Area = Width * Length<BR>\n" );
document.write( "Width = 13 * 21<BR>\n" );
document.write( "Width = 273 feet^2<BR>\n" );
document.write( "Hope this helps.<BR>\n" );
document.write( ":-) </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );