document.write( "Question 787091: a chemist has two solutions of h2so4 one has a 40% concentration and the other has a 25% concentration how many liters of each solution must be mixed to obtain 62 liters of a 31% solution \n" ); document.write( "
Algebra.Com's Answer #478080 by wilft1(217)![]() ![]() You can put this solution on YOUR website! separate the information\r \n" ); document.write( "\n" ); document.write( "2 solutions, we'll call them x and y\r \n" ); document.write( "\n" ); document.write( "x + y = 62 liters\r \n" ); document.write( "\n" ); document.write( ".4x + .25y = .31% solution\r \n" ); document.write( "\n" ); document.write( "multiply 62 liters by .31 percent solution\r \n" ); document.write( "\n" ); document.write( ".4x + .25y = 19.22\r \n" ); document.write( "\n" ); document.write( "lets get rid of the decimal points by moving them over...\r \n" ); document.write( "\n" ); document.write( "x + y = 62 \n" ); document.write( "40x + 25y = 1922\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "now, lets do this using the subtraction method, multiply the top line by - 25 \n" ); document.write( "then subtract to the bottom equation \n" ); document.write( "-25x - 26y = -1550 \n" ); document.write( "40x + 26y = 1922\r \n" ); document.write( "\n" ); document.write( "15x = 372\r \n" ); document.write( "\n" ); document.write( "divide both sides (of the bottom equation) by 15\r \n" ); document.write( "\n" ); document.write( "x = 24.8 liters\r \n" ); document.write( "\n" ); document.write( "now that we know what x is, we plug that into the original equation and find out what y is...\r \n" ); document.write( "\n" ); document.write( "24.8 + y = 62\r \n" ); document.write( "\n" ); document.write( "y = 37.2 liters\r \n" ); document.write( "\n" ); document.write( "solution 40% solution will be 24.8 liters, 25% solution will be 37.2 liters\r \n" ); document.write( "\n" ); document.write( "hope this helps :) \n" ); document.write( " |