document.write( "Question 787091: a chemist has two solutions of h2so4 one has a 40% concentration and the other has a 25% concentration how many liters of each solution must be mixed to obtain 62 liters of a 31% solution \n" ); document.write( "
Algebra.Com's Answer #478080 by wilft1(217)\"\" \"About 
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separate the information\r
\n" ); document.write( "\n" ); document.write( "2 solutions, we'll call them x and y\r
\n" ); document.write( "\n" ); document.write( "x + y = 62 liters\r
\n" ); document.write( "\n" ); document.write( ".4x + .25y = .31% solution\r
\n" ); document.write( "\n" ); document.write( "multiply 62 liters by .31 percent solution\r
\n" ); document.write( "\n" ); document.write( ".4x + .25y = 19.22\r
\n" ); document.write( "\n" ); document.write( "lets get rid of the decimal points by moving them over...\r
\n" ); document.write( "\n" ); document.write( "x + y = 62
\n" ); document.write( "40x + 25y = 1922\r
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\n" ); document.write( "\n" ); document.write( "now, lets do this using the subtraction method, multiply the top line by - 25
\n" ); document.write( "then subtract to the bottom equation
\n" ); document.write( "-25x - 26y = -1550
\n" ); document.write( "40x + 26y = 1922\r
\n" ); document.write( "\n" ); document.write( "15x = 372\r
\n" ); document.write( "\n" ); document.write( "divide both sides (of the bottom equation) by 15\r
\n" ); document.write( "\n" ); document.write( "x = 24.8 liters\r
\n" ); document.write( "\n" ); document.write( "now that we know what x is, we plug that into the original equation and find out what y is...\r
\n" ); document.write( "\n" ); document.write( "24.8 + y = 62\r
\n" ); document.write( "\n" ); document.write( "y = 37.2 liters\r
\n" ); document.write( "\n" ); document.write( "solution 40% solution will be 24.8 liters, 25% solution will be 37.2 liters\r
\n" ); document.write( "\n" ); document.write( "hope this helps :)
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