document.write( "Question 67215This question is from textbook Advanced mathematics
\n" ); document.write( ": On the 24-mile trip to school, Brandon sauntered at a leisurely pace. Thus, he had to double his speed on the way back to complete the trip in 9 hours. How fast did he travel in each direction, and what were the two times? \n" ); document.write( "
Algebra.Com's Answer #47807 by ptaylor(2198)\"\" \"About 
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\n" ); document.write( "Let x=his speed to school
\n" ); document.write( "Then 2x=his speed back\r
\n" ); document.write( "\n" ); document.write( "We are told that the total trip (to & back) is 48 mi\r
\n" ); document.write( "\n" ); document.write( "We are also told that the time to school plus the time back equals 9 hours\r
\n" ); document.write( "\n" ); document.write( "We'll use the formula: distance(d) =rate(r) times time (t) or d=rt and
\n" ); document.write( "t=d/r\r
\n" ); document.write( "\n" ); document.write( "time to school: 24/x\r
\n" ); document.write( "\n" ); document.write( "time from school: 24/2x\r
\n" ); document.write( "\n" ); document.write( "Our equation to solve is
\n" ); document.write( "24/x+24/(2x)=9 multiply through by x
\n" ); document.write( "24(x/x)+24(x/2x)=9x simplifying
\n" ); document.write( "24+12=9x\r
\n" ); document.write( "\n" ); document.write( "9x=36
\n" ); document.write( "x=4 miles per hour ---------speed to school
\n" ); document.write( "time to school: 24/x=24/4=6 hours-----------time to school\r
\n" ); document.write( "\n" ); document.write( "2x=2*4=8 miles per hour---------------rate from school
\n" ); document.write( "time from school: 24/2x=24/8=3 hours ----time from school\r
\n" ); document.write( "\n" ); document.write( "CK\r
\n" ); document.write( "\n" ); document.write( "6 hours + 3 hours = 9 hours\r
\n" ); document.write( "\n" ); document.write( "8 miles per hour = 2 times 4 miles per hour\r
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\n" ); document.write( "\n" ); document.write( "Hope this helps ----ptaylor\r
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