document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=787038>Question 787038</A>: <I><SPAN STYLE=\"word-break: break-all;\"> please solve this equation by factorization 2y2-5y-3=0 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #478048 by </B><A HREF=/tutors/aboutme.mpl?userid=harpazo><B>harpazo(655)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=harpazo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=harpazo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=478048\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2y^2-5y-3=0\r<BR>\n" );
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document.write( "Factor by grouping.\r<BR>\n" );
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document.write( "2y^2-6y+y-3 = 0\r<BR>\n" );
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document.write( "Factor 2y^2-6y to be 2y(y-3)\r<BR>\n" );
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document.write( "We now have 2y(y-3)(y-3).\r<BR>\n" );
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document.write( "We only need one (y-3).\r<BR>\n" );
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document.write( "The other factor is 2y+1.\r<BR>\n" );
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document.write( "Answer: (2y+1)(y-3) </SPAN>\n" );
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