document.write( "Question 786982: Solve by substitution method
\n" ); document.write( "7x+6y=-10
\n" ); document.write( "-8x+y=36 \n" ); document.write( "
Algebra.Com's Answer #478030 by mananth(16946)\"\" \"About 
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7 x + 6 y = -10 .............1
\n" ); document.write( "6 y = -10 + -7 x
\n" ); document.write( "/ 6 =
\n" ); document.write( " y = -5/3 + -1 1/6 x
\n" ); document.write( "-8 x + 1 y = 36 .....................2
\n" ); document.write( "Substitute y in (2)
\n" ); document.write( "-8 x + 1 ( -1 2/3 + -1 1/6 x ) = 36
\n" ); document.write( "-8 x + -5/3 + -7/6 x = 36
\n" ); document.write( "-8 x -7/6 x = 113/3
\n" ); document.write( "-55/6 x = 113/3
\n" ); document.write( "/ -55/6
\n" ); document.write( "x= -37/9
\n" ); document.write( "Plug the value of x in (1)
\n" ); document.write( "7 x + 6 y = -10
\n" ); document.write( "7 * -37/9 + 6 y = -10
\n" ); document.write( "-115/4 + 6 y = -10
\n" ); document.write( "6 y = 75/4
\n" ); document.write( "/ 6
\n" ); document.write( "y= 25/8
\n" ); document.write( "m.ananth@hotmail.ca
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