document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=786889>Question 786889</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I am needing help figuring out this problem. I have tried several ways but can not figure it out.<BR>\n" );
document.write( "\"A liquid that is 55% muriatic acid is added to 4 L of liquid that is 80% muriatic acid how many liters of the 55% solution must be used to produce a new liquid that is 65% muriatic acid\" </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #478018 by </B><A HREF=/tutors/aboutme.mpl?userid=KMST><B>KMST(5328)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=KMST><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=KMST><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=478018\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> As a chemist, I would advice you not to do that. The solution will get hot, may boil over violently, and you could get burnt. Luckily this is just a math problem, and science does not apply, so we can assume that it can be done and that volumes are additive, too.<BR>\n" );
document.write( " <BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x ALIGN=MIDDLE  ALT=\"x\"   DISABLED_style= \"max-width:90%; height:auto;\" >= amount of 55% muriatic acid added, in liters.<BR>\n" );
document.write( "The amount of muriatic acid in that is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=0.55x ALIGN=MIDDLE  ALT=\"0.55x\"   DISABLED_style= \"max-width:90%; height:auto;\" > (I won't even ask if it's in liters or kilograms).<BR>\n" );
document.write( "The amount of muriatic acid in the 4 liters of 80% muriatic acid is<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=0.80%2A4=3.20 ALIGN=MIDDLE  ALT=\"0.80%2A4=3.20\"   DISABLED_style= \"max-width:90%; height:auto;\" > (in the same L or kg units).<BR>\n" );
document.write( "The total amount of muriatic acid in the final mixture will be<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=0.55x%2B3.20 ALIGN=MIDDLE  ALT=\"0.55x%2B3.20\"   DISABLED_style= \"max-width:90%; height:auto;\" >.<BR>\n" );
document.write( "The final volume (in math class, if not in real life) will be<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=4%2Bx ALIGN=MIDDLE  ALT=\"4%2Bx\"   DISABLED_style= \"max-width:90%; height:auto;\" > liters.<BR>\n" );
document.write( "Since those <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=4%2Bx ALIGN=MIDDLE  ALT=\"4%2Bx\"   DISABLED_style= \"max-width:90%; height:auto;\" > liters of final solution will be 65% muriatic acid, we can also calculate the amount of muriatic acid in the final mixture as<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=0.65%284%2Bx%29=2.6%2B0.65x ALIGN=MIDDLE  ALT=\"0.65%284%2Bx%29=2.6%2B0.65x\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "So, <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2.6%2B0.65x=0.55x%2B3.2 ALIGN=MIDDLE  ALT=\"2.6%2B0.65x=0.55x%2B3.2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( " <BR>\n" );
document.write( "Solving <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2.6%2B0.65x=0.55x%2B3.2 ALIGN=MIDDLE  ALT=\"2.6%2B0.65x=0.55x%2B3.2\"   DISABLED_style= \"max-width:90%; height:auto;\" >:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=0.65x=0.55x%2B0.6 ALIGN=MIDDLE  ALT=\"0.65x=0.55x%2B0.6\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=0.65x-0.55x=0.6 ALIGN=MIDDLE  ALT=\"0.65x-0.55x=0.6\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=0.1x=0.6 ALIGN=MIDDLE  ALT=\"0.1x=0.6\"   DISABLED_style= \"max-width:90%; height:auto;\" > and multiplying both sides by 10 (or dividing both by 0.1, same thing)<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight%28x=6%29 ALIGN=MIDDLE  ALT=\"highlight%28x=6%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "So you are expected to add the 4L of 80% acid to <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight%286L%29 ALIGN=MIDDLE  ALT=\"highlight%286L%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > of 55% acid.<BR>\n" );
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