document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=786875>Question 786875</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how do I solve 2c + 3 = 4 (c -1) and 9 - (3r - 1) = 12? please help quick </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #477986 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39621)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=477986\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Solve those?\r<BR>\n" );
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document.write( "I will do the second equation but not to completion.\r<BR>\n" );
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document.write( "9-(3r-1)=12<BR>\n" );
document.write( "-3r+1=12-9<BR>\n" );
document.write( "3r-1=-(12-9)<BR>\n" );
document.write( "3r=1+(-12)+9<BR>\n" );
document.write( "Can you finish? </SPAN>\n" );
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