document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=786825>Question 786825</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 6-x/x+2>1. solve rational inequality. write solution set in interval notation </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #477979 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=477979\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (6-x)/(x+2)>1<BR>\n" );
document.write( "(6-x)/(x+2) - 1 > 0<BR>\n" );
document.write( "((6-x)-(x+2))/(x+2)>0<BR>\n" );
document.write( "(6-x-x-2)/(x+2)>0<BR>\n" );
document.write( "(-2x+4)/(x+2)>0<BR>\n" );
document.write( "-2x+4=0 when x=2 <BR>\n" );
document.write( "x+2=0 when x=-2<BR>\n" );
document.write( "In the interval lower than x=-2 (6-x)/(x+2)<0<BR>\n" );
document.write( "In the interval between x=-2 and x=2  (6-x)/(x+2)>0<BR>\n" );
document.write( "In the interval above x=2 (6-x)/(x+2)<0<BR>\n" );
document.write( "So (-2, 2] The denominator cannot be -2 because division by zero is not allowed.<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Ed<BR>\n" );
document.write( ".<BR>\n" );
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