document.write( "Question 786793: The length of a rectangle is 4 times the width. The perimeter is 35 meters Find the width. \n" ); document.write( "
Algebra.Com's Answer #477973 by MathLover1(20855)\"\" \"About 
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\n" ); document.write( "The length \"L\" of a rectangle is \"4\" times the width \"W\":\r
\n" ); document.write( "\n" ); document.write( "\"L=4W\"\r
\n" ); document.write( "\n" ); document.write( "The perimeter \"P=35m\" \r
\n" ); document.write( "\n" ); document.write( "Find the width.\r
\n" ); document.write( "\n" ); document.write( "\"P=2%28L%2BW%29\" ....substitute \"P=35m\" and \"L=4W\"\r
\n" ); document.write( "\n" ); document.write( "\"35m=2%284W%2BW%29\" ......solve for \"W\"\r
\n" ); document.write( "\n" ); document.write( "\"35m%2F2=5W\"\r
\n" ); document.write( "\n" ); document.write( "\"17.5m=5W\"\r
\n" ); document.write( "\n" ); document.write( "\"17.5m%2F5=W\"\r
\n" ); document.write( "\n" ); document.write( "\"W=3.5m%2F5\"\r
\n" ); document.write( "\n" ); document.write( "now we can find \"L\"\r
\n" ); document.write( "\n" ); document.write( "\"L=4W\"\r
\n" ); document.write( "\n" ); document.write( "\"L=4%2A3.5m\"\r
\n" ); document.write( "\n" ); document.write( "\"L=14m\"\r
\n" ); document.write( "\n" ); document.write( "check the perimeter\r
\n" ); document.write( "\n" ); document.write( "\"P=2%28L%2BW%29\"\r
\n" ); document.write( "\n" ); document.write( "\"P=2%2814m%2B3.5m%29\"\r
\n" ); document.write( "\n" ); document.write( "\"P=2%2817.5m%29\"\r
\n" ); document.write( "\n" ); document.write( "\"P=35m\" which confirms our solution\r
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