document.write( "Question 786565: tan x + √3= 0 → tan x =−√3
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\n" ); document.write( " The term tan x is now isolated in the equation. Find a particular solution on the interval (0, π).
\n" ); document.write( "x =2π/3 , 0 < x < π\r
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\n" ); document.write( "\n" ); document.write( "On (-Infiniti, infiniti ), there are an infinite number of solutions. Write the general form of the solution. Your answer should be exact. (Use n as an integer constant. Enter your response in radians.)\r
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Algebra.Com's Answer #477907 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
The tan is negative in the 2nd and 4th quadrants.
\n" ); document.write( "Between \"+0+\" and \"+2%2Api+\" radians, the solutions
\n" ); document.write( "are \"+x+=+%282%2Api%29%2F3+\" and \"+x+=+%28+5%2Api%29%2F3+\"
\n" ); document.write( "At both these angles, \"+tan%28x%29+=+-sqrt%283%29+%2F+1+\"
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\n" ); document.write( "Now you have to go to \"+2%2Api+%2B+%282%2Api%29%2F3+=+%288%2Api%29%2F3+\"
\n" ); document.write( "and then to \"+2%2Api+%2B+%285%2Api%29%2F3++=+11%2Api%2F3+\"
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\n" ); document.write( "The progression is:
\n" ); document.write( "\"+%282%2Api%29%2F3+\"
\n" ); document.write( "\"+%285%2Api%29%2F3+\"
\n" ); document.write( "\"+%288%2Api%29%2F3+\"
\n" ); document.write( "\"+%2811%2Api%29%2F3+\"
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\n" ); document.write( "The general formula would be
\n" ); document.write( "\"+x+=+%28%28+2+%2B+3n+%29%2Api%29+%2F+3+\" ( n = 0,1,2... )\r
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