document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=8608>Question 8608</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how would I factor the equation (c + 3)^2 - 49 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #4779 by </B><A HREF=/tutors/aboutme.mpl?userid=rapaljer><B>rapaljer(4671)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rapaljer><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rapaljer><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=4779\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> This is NOT an equation, so you can't solve for c, as was done in the previous solution that was posted by a tutor.  The problem is to FACTOR the expression, NOT to SOLVE the equation!!\r<BR>\n" );
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document.write( "It should be <BR>\n" );
document.write( "( (c+3) - 7 )( (c+3) + 7)\r<BR>\n" );
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document.write( "This simplifies to <BR>\n" );
document.write( "(c-4)(c+10)\r<BR>\n" );
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document.write( "R^2 at SCC </SPAN>\n" );
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