document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=786548>Question 786548</A>: <I><SPAN STYLE=\"word-break: break-all;\"> h(x)= -x^2+1 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #477896 by </B><A HREF=/tutors/aboutme.mpl?userid=dfollett76><B>dfollett76(12)</B></A><img src=\"/images/stars/stars-06.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=dfollett76><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=477896\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Before we graph it we know that it will point down since the coefficient on x^2 is negative, and it will have a y-intercept of 1 since h(0)=1 i.e. plug in x = 0.\r<BR>\n" );
document.write( "\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=graph%28500%2C+500%2C+-5%2C+5%2C+-5%2C+5%2C+-x%5E2%2B1%29 ALIGN=MIDDLE  ALT=\"graph%28500%2C+500%2C+-5%2C+5%2C+-5%2C+5%2C+-x%5E2%2B1%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );