document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=786378>Question 786378</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A car leaves town heading west at 57 km/h.<BR>\n" );
document.write( "a) How far will the car travel in 7 hours?<BR>\n" );
document.write( "b) A second car leaves town 2 hours after the first car, but it is traveling at 72 km/h. To the nearest hour, when will the second car pass the first? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #477877 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=477877\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Car A -- 57km/h - 7 hours\r<BR>\n" );
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document.write( "Distance = 399 km distance\r<BR>\n" );
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document.write( "Car A travels 57*2=114 km in 2 hours \r<BR>\n" );
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document.write( "it is 114 km ahead when Car B starts\r<BR>\n" );
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document.write( "Car B rate = 72 km/h\r<BR>\n" );
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document.write( "catch up speed = 72-57=15 km/h\r<BR>\n" );
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document.write( "distance = 114 to catch up<BR>\n" );
document.write( "t=d/r<BR>\n" );
document.write( "t=114/15<BR>\n" );
document.write( "t= 7.6 hours to catch up\r<BR>\n" );
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document.write( " </SPAN>\n" );
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