document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=786386>Question 786386</A>: <I><SPAN STYLE=\"word-break: break-all;\"> It takes Dan 2 hours to paddle his canoe 16 miles downstream, and 8 hours to return to the campsite. Find the speed of the canoe in still water. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #477874 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=477874\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> It takes Dan 2 hours to paddle his canoe 16 miles downstream, and 8 hours to return to the campsite. Find the speed of the canoe in still water.\r<BR>\n" );
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document.write( "canoe rate =x<BR>\n" );
document.write( "current rate = y\r<BR>\n" );
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document.write( "downstream rate = x+y.................2 hours..................16 miles<BR>\n" );
document.write( "upstream rate = x-y...............8 hours...................16\r<BR>\n" );
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document.write( "t=d/r\r<BR>\n" );
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document.write( "16/(x+y)=2<BR>\n" );
document.write( "simplify\r<BR>\n" );
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document.write( "x+y=8\r<BR>\n" );
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document.write( "16/(x-y)=8<BR>\n" );
document.write( "x-y=2\r<BR>\n" );
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document.write( "add the two equations<BR>\n" );
document.write( "2x=10\r<BR>\n" );
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document.write( "x=5 mph canoe speed </SPAN>\n" );
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