document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=786387>Question 786387</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the equation of the line that contains the given point and has the given slope.<BR>\n" );
document.write( "P(&#8722;1, &#8722;3), m =2/3<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #477873 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=477873\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> P(-1,-3) slope = 2/3\r<BR>\n" );
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document.write( "The equation when slope and point are given\r<BR>\n" );
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document.write( "(y-y1)=m(x-x1)<BR>\n" );
document.write( "X1y1 are the points and slope =m\r<BR>\n" );
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document.write( "y-(-3)=2/3(x-(-1)\r<BR>\n" );
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document.write( "y+3=-2/3(x+1)\r<BR>\n" );
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document.write( "y= -2/3 x -(2/3)-3\r<BR>\n" );
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document.write( "y=2/3 x -11/3\r<BR>\n" );
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