document.write( "Question 786343: a train cover certain distance between two places at uniform speed if train move 10km/hr faster it will take 2 hours less.if train move 10km/hr slower it will take 3 hours more than the scheduled time what is distance covered by train \n" ); document.write( "
Algebra.Com's Answer #477868 by mananth(16946) You can put this solution on YOUR website! a train cover certain distance between two places at uniform speed if train move 10km/hr faster it will take 2 hours less.if train move 10km/hr slower it will take 3 hours more than the scheduled time what is distance covered by train\r \n" ); document.write( "\n" ); document.write( "let distance =x \n" ); document.write( "and rate for scheduled time be r \n" ); document.write( "let time be t\r \n" ); document.write( "\n" ); document.write( "x=rt\r \n" ); document.write( "\n" ); document.write( "x/(r+10)=t-2 \n" ); document.write( "x=(t-2)(r+10)\r \n" ); document.write( "\n" ); document.write( "x/(r-10)=t+3 \n" ); document.write( "x=(t+3)(r-10)\r \n" ); document.write( "\n" ); document.write( "(t-2)(r+10)=rt \n" ); document.write( "tr+10t-2r-20=rt \n" ); document.write( "10t-2r=20....................(1)\r \n" ); document.write( "\n" ); document.write( "(t+3)(r-10)=rt \n" ); document.write( "tr-10t+3r-30=rt \n" ); document.write( "-10t+3r=30.....................(2)\r \n" ); document.write( "\n" ); document.write( "add (1) & (2)\r \n" ); document.write( "\n" ); document.write( "r=50 \n" ); document.write( "plug r in (1) \n" ); document.write( "10t-100=20 \n" ); document.write( "10t=120 \n" ); document.write( "/10 \n" ); document.write( "t=12 \r \n" ); document.write( "\n" ); document.write( "x=rt \n" ); document.write( "x=600 miles\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |