document.write( "Question 785437: An open rectangular tank is made from a steel plate of area 1440msquared. Its length is twice its width. If the dept of the tank is 4m lesth than the width, find the length of the tank. \n" ); document.write( "
Algebra.Com's Answer #477782 by KMST(5328)\"\" \"About 
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\"W\"= width in meters
\n" ); document.write( "\"L=2W\"= length in meters
\n" ); document.write( "\"D=W-4\"= depth in meters
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\n" ); document.write( "Obviously, the entire 1440m^2 of the steel plate will be used, without wasting any, or stetching/deforming the material.
\n" ); document.write( "That is probably far from realistic, but this is just a math problem.
\n" ); document.write( "We cannot expect to work on the design, because we have not given enough information. The design is someone else's problem.
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\n" ); document.write( "The total surface of the tank includes the bottom, \"WL\"\"m%5E2\",
\n" ); document.write( "and the sides, \"2%28W%2BL%29D\"\"m%5E2\".
\n" ); document.write( "Our equation is
\n" ); document.write( "\"WL%2B2%28W%2BL%29D=1440\"
\n" ); document.write( "Since L and W came expressed in terms of W, we can substitute those expressions to get an equation in terms of W only:
\n" ); document.write( "\"W%282W%29%2B2%28W%2B2W%29%28W-4%29=1440\"
\n" ); document.write( "\"2W%5E2%2B2%283W%29%28W-4%29=1440\"
\n" ); document.write( "\"2W%5E2%2B6W%28W-4%29=1440\"
\n" ); document.write( "\"2W%5E2%2B6W%5E2-24W=1440\"
\n" ); document.write( "\"2W%5E2%2B6W%5E2-24W-1440=0\"
\n" ); document.write( "\"8W%5E2-24W-1440=0\"
\n" ); document.write( "Dividing both sides of the equal sign by 8, we get
\n" ); document.write( "\"W%5E2-3W-180=0\"
\n" ); document.write( "Factoring, we get
\n" ); document.write( "\"%28W-15%29%28W%2B12%29=0\" with solutions \"W=15\" and \"W=-12\"
\n" ); document.write( "We throw away \"W=-12\" because the width in meters cannot be a negative number.
\n" ); document.write( "\"w=15\" --> \"l=2W=2%2A15=highlight%2830%29\"
\n" ); document.write( "The length of the tank is \"highlight%2830m%29\"
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