document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=785861>Question 785861</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If the length of a rectangle is twice its width.if the length of the diagonal of the rectangle is square root of 15, fint the length of the rectangle.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #477747 by </B><A HREF=/tutors/aboutme.mpl?userid=vic21><B>vic21(4)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=vic21><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=477747\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> c^2 = a^2 + b^2 \r<BR>\n" );
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document.write( "&#8730;15 is the hypotenuse\r<BR>\n" );
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document.write( "if L = 2W\r<BR>\n" );
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document.write( "then\r<BR>\n" );
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document.write( "(2W)^2 + W^2 = (&#8730;15)^2\r<BR>\n" );
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document.write( "4W^2 + W^2 = 15\r<BR>\n" );
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document.write( "5w^2 = 15\r<BR>\n" );
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document.write( "w^2 = 15/5 = 3\r<BR>\n" );
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document.write( "w= &#8730;3\r<BR>\n" );
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document.write( "then from L=2W<BR>\n" );
document.write( "L= 2(&#8730;3)\r<BR>\n" );
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document.write( "ANSWER : L = 2&#8730;3 or 3.46 \r<BR>\n" );
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