document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=785849>Question 785849</A>: <I><SPAN STYLE=\"word-break: break-all;\"> seven consecutive natural numbers have a sum equal to 105. how many are divisible by 5<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #477743 by </B><A HREF=/tutors/aboutme.mpl?userid=vic21><B>vic21(4)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=vic21><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=477743\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1x+2x+3x+4x+5x+6x+7x=105\r<BR>\n" );
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document.write( "28x=105\r<BR>\n" );
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document.write( "x= 3.75\r<BR>\n" );
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document.write( "1(3.75)= 3.75<BR>\n" );
document.write( "2(3.75)= 7.5<BR>\n" );
document.write( "3(3.75)= 11.25<BR>\n" );
document.write( "4(3.75)=15 ( only number divisible by 5)<BR>\n" );
document.write( "5(3.75)=18.75<BR>\n" );
document.write( "6((3.75)=22.5<BR>\n" );
document.write( "7((3.75)=26.25\r<BR>\n" );
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document.write( "answer only 1 is divisible by 5 </SPAN>\n" );
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